Integrand size = 29, antiderivative size = 291 \[ \int \frac {\log \left (e \left (\frac {a+b x}{c+d x}\right )^n\right )}{f-g x^2} \, dx=\frac {\log \left (e \left (\frac {a+b x}{c+d x}\right )^n\right ) \log \left (1-\frac {\left (d \sqrt {f}-c \sqrt {g}\right ) (a+b x)}{\left (b \sqrt {f}-a \sqrt {g}\right ) (c+d x)}\right )}{2 \sqrt {f} \sqrt {g}}-\frac {\log \left (e \left (\frac {a+b x}{c+d x}\right )^n\right ) \log \left (1-\frac {\left (d \sqrt {f}+c \sqrt {g}\right ) (a+b x)}{\left (b \sqrt {f}+a \sqrt {g}\right ) (c+d x)}\right )}{2 \sqrt {f} \sqrt {g}}+\frac {n \operatorname {PolyLog}\left (2,\frac {\left (d \sqrt {f}-c \sqrt {g}\right ) (a+b x)}{\left (b \sqrt {f}-a \sqrt {g}\right ) (c+d x)}\right )}{2 \sqrt {f} \sqrt {g}}-\frac {n \operatorname {PolyLog}\left (2,\frac {\left (d \sqrt {f}+c \sqrt {g}\right ) (a+b x)}{\left (b \sqrt {f}+a \sqrt {g}\right ) (c+d x)}\right )}{2 \sqrt {f} \sqrt {g}} \]
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Time = 0.24 (sec) , antiderivative size = 291, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.138, Rules used = {2576, 2404, 2354, 2438} \[ \int \frac {\log \left (e \left (\frac {a+b x}{c+d x}\right )^n\right )}{f-g x^2} \, dx=\frac {\log \left (e \left (\frac {a+b x}{c+d x}\right )^n\right ) \log \left (1-\frac {(a+b x) \left (d \sqrt {f}-c \sqrt {g}\right )}{(c+d x) \left (b \sqrt {f}-a \sqrt {g}\right )}\right )}{2 \sqrt {f} \sqrt {g}}-\frac {\log \left (e \left (\frac {a+b x}{c+d x}\right )^n\right ) \log \left (1-\frac {(a+b x) \left (c \sqrt {g}+d \sqrt {f}\right )}{(c+d x) \left (a \sqrt {g}+b \sqrt {f}\right )}\right )}{2 \sqrt {f} \sqrt {g}}+\frac {n \operatorname {PolyLog}\left (2,\frac {\left (d \sqrt {f}-c \sqrt {g}\right ) (a+b x)}{\left (b \sqrt {f}-a \sqrt {g}\right ) (c+d x)}\right )}{2 \sqrt {f} \sqrt {g}}-\frac {n \operatorname {PolyLog}\left (2,\frac {\left (\sqrt {g} c+d \sqrt {f}\right ) (a+b x)}{\left (\sqrt {g} a+b \sqrt {f}\right ) (c+d x)}\right )}{2 \sqrt {f} \sqrt {g}} \]
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Rule 2354
Rule 2404
Rule 2438
Rule 2576
Rubi steps \begin{align*} \text {integral}& = (b c-a d) \text {Subst}\left (\int \frac {\log \left (e x^n\right )}{b^2 f-a^2 g-(2 b d f-2 a c g) x+\left (d^2 f-c^2 g\right ) x^2} \, dx,x,\frac {a+b x}{c+d x}\right ) \\ & = (b c-a d) \text {Subst}\left (\int \left (\frac {\left (d^2 f-c^2 g\right ) \log \left (e x^n\right )}{(b c-a d) \sqrt {f} \sqrt {g} \left (2 b d f-2 (b c-a d) \sqrt {f} \sqrt {g}-2 a c g-2 \left (d^2 f-c^2 g\right ) x\right )}+\frac {\left (d^2 f-c^2 g\right ) \log \left (e x^n\right )}{(b c-a d) \sqrt {f} \sqrt {g} \left (-2 b d f-2 (b c-a d) \sqrt {f} \sqrt {g}+2 a c g+2 \left (d^2 f-c^2 g\right ) x\right )}\right ) \, dx,x,\frac {a+b x}{c+d x}\right ) \\ & = \frac {\left (d^2 f-c^2 g\right ) \text {Subst}\left (\int \frac {\log \left (e x^n\right )}{2 b d f-2 (b c-a d) \sqrt {f} \sqrt {g}-2 a c g-2 \left (d^2 f-c^2 g\right ) x} \, dx,x,\frac {a+b x}{c+d x}\right )}{\sqrt {f} \sqrt {g}}+\frac {\left (d^2 f-c^2 g\right ) \text {Subst}\left (\int \frac {\log \left (e x^n\right )}{-2 b d f-2 (b c-a d) \sqrt {f} \sqrt {g}+2 a c g+2 \left (d^2 f-c^2 g\right ) x} \, dx,x,\frac {a+b x}{c+d x}\right )}{\sqrt {f} \sqrt {g}} \\ & = \frac {\log \left (e \left (\frac {a+b x}{c+d x}\right )^n\right ) \log \left (1-\frac {\left (d \sqrt {f}-c \sqrt {g}\right ) (a+b x)}{\left (b \sqrt {f}-a \sqrt {g}\right ) (c+d x)}\right )}{2 \sqrt {f} \sqrt {g}}-\frac {\log \left (e \left (\frac {a+b x}{c+d x}\right )^n\right ) \log \left (1-\frac {\left (d \sqrt {f}+c \sqrt {g}\right ) (a+b x)}{\left (b \sqrt {f}+a \sqrt {g}\right ) (c+d x)}\right )}{2 \sqrt {f} \sqrt {g}}+\frac {n \text {Subst}\left (\int \frac {\log \left (1-\frac {2 \left (d^2 f-c^2 g\right ) x}{2 b d f-2 (b c-a d) \sqrt {f} \sqrt {g}-2 a c g}\right )}{x} \, dx,x,\frac {a+b x}{c+d x}\right )}{2 \sqrt {f} \sqrt {g}}-\frac {n \text {Subst}\left (\int \frac {\log \left (1+\frac {2 \left (d^2 f-c^2 g\right ) x}{-2 b d f-2 (b c-a d) \sqrt {f} \sqrt {g}+2 a c g}\right )}{x} \, dx,x,\frac {a+b x}{c+d x}\right )}{2 \sqrt {f} \sqrt {g}} \\ & = \frac {\log \left (e \left (\frac {a+b x}{c+d x}\right )^n\right ) \log \left (1-\frac {\left (d \sqrt {f}-c \sqrt {g}\right ) (a+b x)}{\left (b \sqrt {f}-a \sqrt {g}\right ) (c+d x)}\right )}{2 \sqrt {f} \sqrt {g}}-\frac {\log \left (e \left (\frac {a+b x}{c+d x}\right )^n\right ) \log \left (1-\frac {\left (d \sqrt {f}+c \sqrt {g}\right ) (a+b x)}{\left (b \sqrt {f}+a \sqrt {g}\right ) (c+d x)}\right )}{2 \sqrt {f} \sqrt {g}}+\frac {n \text {Li}_2\left (\frac {\left (d \sqrt {f}-c \sqrt {g}\right ) (a+b x)}{\left (b \sqrt {f}-a \sqrt {g}\right ) (c+d x)}\right )}{2 \sqrt {f} \sqrt {g}}-\frac {n \text {Li}_2\left (\frac {\left (d \sqrt {f}+c \sqrt {g}\right ) (a+b x)}{\left (b \sqrt {f}+a \sqrt {g}\right ) (c+d x)}\right )}{2 \sqrt {f} \sqrt {g}} \\ \end{align*}
Time = 0.08 (sec) , antiderivative size = 421, normalized size of antiderivative = 1.45 \[ \int \frac {\log \left (e \left (\frac {a+b x}{c+d x}\right )^n\right )}{f-g x^2} \, dx=\frac {n \log \left (\frac {\sqrt {g} (a+b x)}{b \sqrt {f}+a \sqrt {g}}\right ) \log \left (\sqrt {f}-\sqrt {g} x\right )-\log \left (e \left (\frac {a+b x}{c+d x}\right )^n\right ) \log \left (\sqrt {f}-\sqrt {g} x\right )-n \log \left (\frac {\sqrt {g} (c+d x)}{d \sqrt {f}+c \sqrt {g}}\right ) \log \left (\sqrt {f}-\sqrt {g} x\right )-n \log \left (-\frac {\sqrt {g} (a+b x)}{b \sqrt {f}-a \sqrt {g}}\right ) \log \left (\sqrt {f}+\sqrt {g} x\right )+\log \left (e \left (\frac {a+b x}{c+d x}\right )^n\right ) \log \left (\sqrt {f}+\sqrt {g} x\right )+n \log \left (-\frac {\sqrt {g} (c+d x)}{d \sqrt {f}-c \sqrt {g}}\right ) \log \left (\sqrt {f}+\sqrt {g} x\right )+n \operatorname {PolyLog}\left (2,\frac {b \left (\sqrt {f}-\sqrt {g} x\right )}{b \sqrt {f}+a \sqrt {g}}\right )-n \operatorname {PolyLog}\left (2,\frac {d \left (\sqrt {f}-\sqrt {g} x\right )}{d \sqrt {f}+c \sqrt {g}}\right )-n \operatorname {PolyLog}\left (2,\frac {b \left (\sqrt {f}+\sqrt {g} x\right )}{b \sqrt {f}-a \sqrt {g}}\right )+n \operatorname {PolyLog}\left (2,\frac {d \left (\sqrt {f}+\sqrt {g} x\right )}{d \sqrt {f}-c \sqrt {g}}\right )}{2 \sqrt {f} \sqrt {g}} \]
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\[\int \frac {\ln \left (e \left (\frac {b x +a}{d x +c}\right )^{n}\right )}{-g \,x^{2}+f}d x\]
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\[ \int \frac {\log \left (e \left (\frac {a+b x}{c+d x}\right )^n\right )}{f-g x^2} \, dx=\int { -\frac {\log \left (e \left (\frac {b x + a}{d x + c}\right )^{n}\right )}{g x^{2} - f} \,d x } \]
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Timed out. \[ \int \frac {\log \left (e \left (\frac {a+b x}{c+d x}\right )^n\right )}{f-g x^2} \, dx=\text {Timed out} \]
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Time = 0.33 (sec) , antiderivative size = 349, normalized size of antiderivative = 1.20 \[ \int \frac {\log \left (e \left (\frac {a+b x}{c+d x}\right )^n\right )}{f-g x^2} \, dx=\frac {{\left (\log \left (\sqrt {g} x - \sqrt {f}\right ) \log \left (\frac {b \sqrt {g} x - b \sqrt {f}}{b \sqrt {f} + a \sqrt {g}} + 1\right ) - \log \left (\sqrt {g} x + \sqrt {f}\right ) \log \left (-\frac {b \sqrt {g} x + b \sqrt {f}}{b \sqrt {f} - a \sqrt {g}} + 1\right ) - \log \left (\sqrt {g} x - \sqrt {f}\right ) \log \left (\frac {d \sqrt {g} x - d \sqrt {f}}{d \sqrt {f} + c \sqrt {g}} + 1\right ) + \log \left (\sqrt {g} x + \sqrt {f}\right ) \log \left (-\frac {d \sqrt {g} x + d \sqrt {f}}{d \sqrt {f} - c \sqrt {g}} + 1\right ) + {\rm Li}_2\left (-\frac {b \sqrt {g} x - b \sqrt {f}}{b \sqrt {f} + a \sqrt {g}}\right ) - {\rm Li}_2\left (\frac {b \sqrt {g} x + b \sqrt {f}}{b \sqrt {f} - a \sqrt {g}}\right ) - {\rm Li}_2\left (-\frac {d \sqrt {g} x - d \sqrt {f}}{d \sqrt {f} + c \sqrt {g}}\right ) + {\rm Li}_2\left (\frac {d \sqrt {g} x + d \sqrt {f}}{d \sqrt {f} - c \sqrt {g}}\right )\right )} n}{2 \, \sqrt {f g}} - \frac {\log \left (e \left (\frac {b x + a}{d x + c}\right )^{n}\right ) \log \left (\frac {g x - \sqrt {f g}}{g x + \sqrt {f g}}\right )}{2 \, \sqrt {f g}} \]
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\[ \int \frac {\log \left (e \left (\frac {a+b x}{c+d x}\right )^n\right )}{f-g x^2} \, dx=\int { -\frac {\log \left (e \left (\frac {b x + a}{d x + c}\right )^{n}\right )}{g x^{2} - f} \,d x } \]
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Timed out. \[ \int \frac {\log \left (e \left (\frac {a+b x}{c+d x}\right )^n\right )}{f-g x^2} \, dx=\int \frac {\ln \left (e\,{\left (\frac {a+b\,x}{c+d\,x}\right )}^n\right )}{f-g\,x^2} \,d x \]
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